Предмет: Алгебра, автор: dah1000

Помогите решить неравенство пожалуйста

Приложения:

Ответы

Автор ответа: dimaogol2000

1

Ответ:

x∈(-∞;-2]∪[2;+∞)

Объяснение:

$2x^2\geq 8<=>x^2\geq 4<=>(x-2)(x+2)\geq 0$

Автор ответа: ilas13

0

Х во второй степени >или= 4

Х принадлежит [4;+бесконечность)

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