Question

Решите пожалуйста систему уравнения ​

Answer 1

$\begin{cases} \frac{15x-3y}{4}+\frac{3x+2y}{6}=3\ \ / *12 \\\frac{3x+y}{3}-\frac{x-3y}{2}=6\ \ /*6 \end{cases}\\\\ \begin{cases} 3(15x-3y)+2(3x+2y )=36 \\2(3x+y)-3( x-3y) =36\end{cases}\\\\\begin{cases} 45x-9y +6x+4y =36 \\6x+2y -3x+9y=36\end{cases}\\\\\begin{cases}51x-5y =36 \\3x+11y=36\ \ /*(-17)\end{cases}\\\\\begin{cases}51x-5y =36 \\-51x-187y=-612\end{cases}\\+----------\\-192y=-576\ \ /:(-192)$

$y=3\\\\3x+11y=36\\3x+11*3=36\\3x+33=36\\3x=36-33\\3x= 3\ \ /:3\\x=1\\\\\begin{cases} x=1 \\y=3 \end{cases}$