Question

y²-6y+9 : 10y-30
------------ ----------
y²-9 y²+3y при y=70
​

Answer 1

$\frac{y^2-6y+9}{y^2-9}:\frac{10y-30}{y^2+3y}=\frac{(y-3)^2}{(y-3)(y+3)}\cdot\frac{y(y+3)}{10(y-3)}=\frac{y}{10}\\\\\frac{y}{10}=\frac{70}{10}=7$

Ответ: 7