Question

6.92 (2,4) ставлю 50 баллов

Answer 1

.................................................

Готово!!!Удачи)))))

_____________________

Answer 2

Задание 2 :

$1)\frac{2m+1}{2m-1}-\frac{2m-1}{2m+1}=\frac{4m^{2}+4m+1-(4m^{2}-4m+1)}{(2m-1)(2m+1)}=\frac{4m^{2}+4m+1-4m^{2}+4m-1}{(4m^{2}-1 }=\frac{8m}{4m^{2}-1 }\\\\2)\frac{8m}{4m^{2}-1 }:\frac{4m}{10m-5}=\frac{8m}{(2m-1)(2m+1)}*\frac{5(2m-1)}{4m}=\frac{10}{2m+1}$

Задание 4 :

$1)\frac{x^{2} }{y^{2} }+\frac{y}{x}=\frac{x^{3}+y^{3}}{xy^{2} }\\\\2)\frac{x}{y^{2} }-\frac{1}{y}+\frac{1}{x}=\frac{x^{2}-xy+y^{2}}{xy^{2} }\\\\3)\frac{x^{3}+y^{3}}{xy^{2}}:\frac{x^{2}-xy+y^{2}}{xy^{2} }=\frac{(x+y)(x^{2}-xy+y^{2})}{xy^{2} }*\frac{xy^{2} }{x^{2}-xy+y^{2}} =x+y$