Question

Решите методом замены системы уравнений:​

Answer 1

$\left \{ {{2\frac{1}{3}x-\frac{1}{9}y=4} \atop {1.6x-\frac{1}{30}y=3}} \right. \Longrightarrow \left \{ {{2\frac{1}{3}x-\frac{1}{9}y=4} \atop {1.6x=3+\frac{1}{30}y}} \right. \Longrightarrow \left \{ {{2\frac{1}{3}x-\frac{1}{9}y=4} \atop {x=1.875+\frac{1}{48}y}} \right. \\\\\\\\2\frac{1}{3}(1.875+\frac{1}{48}y)-\frac{1}{9}y=4\\\\4.375+\frac{7}{144}y-\frac{1}{9}y=4\\\\4.375-\frac{1}{16}y=4\\\\y=6\\\\\\\\x=1.875+\frac{1}{48}*6\\\\x=1.875+0.125\\\\x=2$

Ответ: х=2; у=6