Question

Решите уравнение: а)(31+а) : 0,9 = 216,4; б)(0,59+9/10×х) × 100 = 959​

Answer 1

$a)\\\\\left[\begin{array}{ccc}(31+a):0,9=216,4\\31+a=216.4*0.9\\31+a=194.76\\a=194.76-31\\a=163.76\end{array}\right]$

$b)\\\\\left[\begin{array}{ccc}(0.59+0.9x)*100=959\\0.59+0.9x=959:100\\0.59+0.9x=9.59\\0.9x=9.59-0.59\\0.9x=9\\x=10\end{array}\right]$