Question

Решите систему уравнений
2√x+y -3√x-y =3
3√x+y +√x-y =10

Answer 1

Ответ:

$(x;y)=(5;4)$

Объяснение:

$\left \{ {{2\sqrt{x+y} -3\sqrt{x-y} =3} \atop {3\sqrt{x+y} +\sqrt{x-y} =10}} \right. <=>\left \{ {{2\sqrt{x+y} -3\sqrt{x-y} =3} \atop {9\sqrt{x+y} +3\sqrt{x-y} =30}} \right.=>11\sqrt{x+y}=33<=>\\<=>\sqrt{x+y}=3<=>x+y=9=>2* \sqrt{9} -3\sqrt{x-y}=3<=>\\<=>\sqrt{x-y}=1<=>x-y=1\\\left \{ {{x+y=9} \atop {x-y=1}} \right.  =>(x;y)=(5;4)$