Question

Решите неравенство 1/8˂2^x-1≤16 СРОЧНО!!!!!!!!!!!!!!!

Answer 1

Ответ:

Объяснение:

$\frac{1}{8}<2^x-1\leq  16<=>\left \{ {{2^x-1>\frac{1}{8} } \atop {2^x-1\leq16 }} \right. =>\left \{ {{2^x>\frac{9}{8} } \atop {2^x\leq 17 }} \right. =>2log_2(3)-3<x\leq log_2(17)$