Question

Сократите дробь: а) 12р6к²/8р⁴к5
Б) 6х+6у/х²-у²

Answer 1

$1)~\displaystyle\tt\frac{12p^6k^2}{8p^4k^5}=\frac{3p^2}{2k^3};\\\\\\2)~\frac{6x+6y}{x^2-y^2}=\frac{6(x+y)}{(x-y)\cdot(x+y)}=\frac{6}{x-y}$