Question

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Answer 1

4a) x² - 5x - 6 = (x - 6)(x + 1)

4б) - 2x² + 5x - 3

- 2x² + 5x - 3 = 0

2x² - 5x + 3 = 0

D = (- 5)² - 4 * 2 * 3 = 25 - 24 = 1

$x_{1}=\frac{5-1}{4} =1\\\\x_{2} =\frac{5+1}{4}=1,5$

- 2x² + 5x - 3 = - 2(x - 1)(x - 1,5)

5)Разложим числитель на множители :

2x² - 5x + 2 = 2(x - 2)(x - 0,5)

Разложим знаменатель на множители :

3x - 6 = 3(x - 2)

$\frac{2x^{2}-5x+2 }{3x-6} =\frac{2(x-2)(x-0,5)}{3(x-2)}=\frac{2x-1}{3}$

$6a)\frac{2a-3b}{4c}*\frac{11c^{2} }{3b-2a}=-\frac{11c}{4}\\\\6b)\frac{x^{2}-3xy }{a+b}:\frac{x-3y}{a^{2}+ab }=\frac{x(x-3y)}{a+b}*\frac{a(a+b)}{x-3y}=ax\\\\6v)\frac{a-b}{a+3b}*\frac{a^{2}-9b^{2}}{a^{2}-b^{2}}=\frac{a-b}{a+3b}*\frac{(a-3b)(a+3b)}{(a-b)(a+b)}=\frac{a-3b}{a+b}$

Answer 2

№4.

1) =х²+х-6х-6=х (х+1)-6 (х+1) = (х+1) (х-6)

2) =-2х²+3х+2х-3=-х (2х-3) +2х-3= (2х-3) (-х+1)

№5.

$= \frac{2x {}^{2} - x - 4x + 2 }{3(x - 2)} = \frac{x(2x - 1) - 2(2x - 1)}{3(x - 2)} = \frac{(2x - 1)(x - 2)}{3(x - 2)} = \frac{2x - 1}{3}$

№6.

$1) = \frac{2a - 3b}{4} \times \frac{11c}{ - (2a - 3b)} = \frac{ - 1}{4} \times 11c = - \frac{11}{4} c = - 2.75c$

$2 )= \frac{x(x - 3y)}{a + b} \times \frac{a {}^{2 } + ab}{x - 3y } = \frac{x}{a + b} \times a \times (a + b) = xa = ax$

$\\ \\ 3) = \frac{a - b}{a + 3b} \times \frac{(a - 3b)(a + 3b)}{(a - b)(a + b)} = \frac{a - 3b}{a + b}$

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