Question

$\frac{10}{x} - \frac{19}{x + 1} = 0.5$
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Answer 1

$\frac{10}{x}-\frac{19}{x+1}=0,5\\\\\frac{10}{x}-\frac{19}{x+1}=\frac{1}{2}\\\\\frac{10x+10-19x}{x(x+1)} =\frac{1}{2}\\\\\frac{-9x+10}{x^{2}+x }=\frac{1}{2}\\\\\left \{ {{x^{2}+x=-18x+20 } \atop {x\neq0;x\neq-1}} \right.\\\\x^{2} +19x-20=0\\\\x_{1}=-20\\\\x_{2}=1$