Question

Найдите производную сложной функции

Answer 1

$y=\frac{4}{(12x-1)^3};f(a)=f^3(12x-1)=f^3(a)\\y'=(\frac{4}{f^3(a)})'=(4*f^{-3}(a))'=4*(-3)*f^{-3-1}(a)*(a)'=-12*f^{-4}(a)*(a)';\\y'=\frac{-12}{(12x-1)^4}*(12x-1)'= \frac{-12*12}{(12x-1)^2}=\frac{-144}{(12x-1)^4}$