Question

решить систему уравнений
3x-2(3y+1)=-2
2(x+1)-1=3y-1​

Answer 1

$3x - 6y = 0 \\ - 4x + 6y = 4 \\ \\ - x = 4 \\ x = - 4 \\ \\ 2 \times ( - 4) - 3y = - 2 \\ \\ y = - 2 \\ \\ \\ ( x \: and \: y) = ( - 4 \: and \: - 2)$