Question

помогите пожалуйста​

Answer 1

$\frac{x {}^{2} + 5x }{x - 1} = \frac{6}{x - 1} \\ x {}^{2} + 5x = 6 \\ x {}^{2} + 5x - 6 = 0 \\ x {}^{2} + 6x - 1x - 6 = 0 \\ x(x - 1) + 6(x - 1) = 0 \\ (x - 1)(x + 6) = 0 \\ x = 1 \\ x = - 6$

вот решение