Предмет: Химия, автор: NikitaSurnaev

Определите массу аммиака, которую можно получить из 200 л воздуха с выходом 85%. Помогите пожалуйста

Ответы

Автор ответа: upikzh

Ответ:

235.3 хг

N+3H2=2NH3

67.2 34г

200л------85%

хл------100%

х= 235.3

х =235.3*34/67.2

х=119 г

Объяснение:

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