Question

найти точки экстремума
$f(x) = 9 {x}^{2} - 4x \\ f(x) = 8x - {x}^{2} \\ f(x) = - {x}^{3} + 3 {x}^{2} + 9x \\ \\ f(x) = 6x - {x}^{2} \\ f(x) = 3 + 2x + {x}^{2} \\ f(x) = - \frac{ {x}^{3} }{3} + 4 {x}^{2} - 7x + 18$
​

Answer 1

Ответ в закрепе..................