Question

1)$5x^{2}$-10=0
2)$x^{2}$+4$x$=0
3)$3x^{2}+7x+2=0$

Answer 1

$1)5x {}^{2} - 10 = 0 \\ \\ x {}^{2} - 2 = 0 \\ \\ x {}^{2} = 2 \\ \\ x1 = - \sqrt{2} \\ \\ x2 = \sqrt{2} \\ \\ \\ \\ 2)x {}^{2} + 4x = 0 \\ \\ x \times (x + 4) = 0 \\ \\ x1 = 0 \\ \\ x + 4 = 0 \\ \\ x2 = - 4 \\ \\ \\ \\ \\ 3)3x {}^{2} + 7x + 2 = 0$

D = ( 7 )² – 4 * 3 * 2 = 49 - 24 = 25

$x1 = \frac{ - 7 - 5}{2 \times 3} \\ \\ x2 = \frac{ - 7 + 5}{2 \times 3} \\ \\ x1 = - 2 \\ \\ x2 = - \frac{2}{6} = - \frac{1}{3}$

~•~•~•ZLOY_TIGROVSKIY~•~•~•