Question

помогите решить номер 9 подскажите плиз​

Answer 1

Решение :

$(2 \frac{13}{48} + 2 \frac{5}{12} ) \div 3 \frac{3}{4} - 9 \frac{3}{4} \div 12$

решаем по действиям :

1)

$2 \frac{13}{18} + 2 \frac{5}{12} = 4 + \frac{13}{18} + \frac{5}{12} = 4 + \frac{26}{36} + \frac{15}{36} = 4 + \frac{41}{36} = 5 \frac{5}{36}$

2)

$9 \frac{3}{4} \div 12 = \frac{39}{4} \div 12 = \frac{39}{48} = \frac{13}{16}$

3)

$5 \frac{5}{36} \div 3 \frac{3}{4} = \frac{185}{36} \div \frac{15}{4} = \frac{185}{36} \times \frac{4}{15} = \frac{740}{540} = \frac{37}{27} = 1 \frac{10}{27}$

4)

$1 \frac{10}{27} - \frac{13}{16} = \frac{37}{27} - \frac{13}{16} = \frac{592}{432} - \frac{351}{432 } = \frac{242}{432}$

Ответ : 242 / 432