Question

Решите пожалуйста ❤️

Answer 1

$1)\; \; f(x)=x^2+2x\\\\f'(x)=2x+2\; ,\; \; f'(-2)=-4+2=-2\; ,\; f'(\frac{1}{2})=1+2=3\\\\\\2)\; \; f(x)=\frac{x+1}{2x-3}\\\\f'(x)=\frac{2x-3-2(x+1)}{(2x-3)^2}=\frac{-5}{(2x-3)^2}\\\\f'(0)=\frac{-5}{(-3)^2}=-\frac{5}{9}\\\\f'(-3)=\frac{-5}{(-9)^2}=-\frac{5}{81}$