Question

Решите уравнение..........

Answer 1

$\frac{18}{x^{2} - 9} + \frac{1}{x-3}= \frac{x}{x+3}$

ОДЗ:

$x\neq 3\\x\neq -3$

$\frac{18+x+3-x*(x-3)}{(x-3)(x+3)}=0$

$\frac{21+4x-x^{2}}{(x-3(x+3)} =0$

$\frac{-(x-7)(x+3)}{(x-3)(x+3)} =0$

$\frac{-(x-7)}{x-3}=0$

-x = -7

x = 7

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Ответ: 7