Question

помогите пожалуйста решить)​

Answer 1

$\begin{equation*} \begin{cases}\tt\cfrac{y}{3}-\cfrac{x}{2} =1 \ \ |\cdot6\\\\ \tt2^{x-2}\cdot2^y=8 \end{cases}\end{equation*} \ \Rightarrow \begin{equation*} \begin{cases}\tt 2y-3x=6 \\\\ \tt2^{x-2+y}=2^3 \end{cases}\end{equation*} \ \Rightarrow \begin{equation*} \begin{cases}\tt 2y-3x=6 \\\\ \tt x-2+y=3 \end{cases}\end{equation*} \ \Rightarrow$

$\displaystyle\tt\Rightarrow\left \{{{2y-3x=6} \atop {x=5-y \ \ \ }} \right. \Rightarrow\left \{{{2y-3(5-y)=6} \atop {x=5-y \ \ \ \ \ \ \ \ \ \ }} \right. \Rightarrow\left \{{{2y-15+3y=6} \atop {x=5-y \ \ \ \ \ \ \ \ \ \ }} \right. \Rightarrow\\\\\\ \Rightarrow\left \{{{5y=21 \ \ \ } \atop {x=5-y}} \right. \Rightarrow\left \{{{y=4,2 \ \ \ } \atop {x=5-y}} \right. \Rightarrow\left \{{{y=4,2 } \atop {x=0,8}} \right.$

Ответ: (0,8; 4,2)