Question

Помогите!! Решите неравенство sin x/3<√3/2

Answer 1

$\sin \frac{x}{3}<\frac{\sqrt{3}}{2}\\ \\ -\frac{4\pi}{3}+2\pi n <\frac{x}{3}<\frac{\pi}{3}+2\pi n,n \in \mathbb{Z}~~~|\cdot 3\\ \\ -4\pi+6\pi n<x<\pi +6\pi n,n \in \mathbb{Z}$