Question

Cosп\6-✓2sinп\4+✓3tgп\3

Answer 1

$Cos\frac{\pi }{6}-\sqrt{2}Sin\frac{\pi }{4}+\sqrt{3}tg\frac{\pi }{3}=\frac{\sqrt{3} }{2}-\sqrt{2}*\frac{\sqrt{2} }{2}+\sqrt{3}*\sqrt{3}=\frac{\sqrt{3} }{2}-1+3=\frac{\sqrt{3} }{2}+2$