Question

Решите уравнение:Log2(3x-7)=4

Answer 1

$log(2) (3x - 7).x > \frac{7}{3}$

$3x - 7 = {2}^{4}$

$3x - 7 = 16$

$3x = 16 + 7$

$3x = 23$

$x = \frac{ 23}{3}.x > \frac{7}{3}$

$x = 7 \frac{2}{3}$

$x = 7.6$