Question

(√10-1) во 2 степени

Answer 1

(√10)^2-2*1*√10+1^2 = 10-2√10+1 =11-2√10

Answer 2

$( \sqrt{10} - 1) ^{2} = 10 - 2 \sqrt{10} + 1 = 11 - 2 \sqrt{10}$