Question

найдите значение дробного выражение ​

Answer 1

$\frac{x^{4}(x+4)}{x^{3}(x+4)} = \frac{x^{4}}{x^{3}} = x = -0.6</p><p>\frac{x^{4}(3x+4)}{x^{2}(3x+4)} = \frac{x^{4}}{x^{2}} = x^{2} = (-3\frac{2}{3}) ^{2} = (-\frac{8}{3}) ^{2}= \frac{64}{9} =7\frac{1}{3}$