Question

∫sin2xcos2x

Answer 1

∫sin2xcos2xdx=1/2∫sin2xd(sin2x)=1/4sin^2(2x)

Answer 2

 2(sin^4 x+sin^2 xcos^2 x+cos^4 x)^2-sin^8 x-cos^8 x. ^4