Предмет: Математика, автор: kamilllllllllaaaa

решите пожалуйста задачу с действиями 18 балллов даю​

Приложения:

Ответы

Автор ответа: prettypushkova
0

Всю работу примем за единицу (целое).

1) 1 : 40 = 1/40 - часть работы, которую выполнит первая бригада за 1 день;

2) 1 : 25 = 1/25 - часть работы, которую выполнят две бригады за 1 день при совместной работе;

3) 1/25 - 1/40 = 8/200 - 5/200 = 3/200 - часть работы, которую выполнит вторая бригада за 1 день;

4) 1 : 3/200 = 1 · 200/3 = 200/3 = 66 целых 2/3 дня - время выполнения всей работы второй бригадой.

Ответ: сможет, так как 66 целых 2/3 < 67 .

Автор ответа: malvina1723
0

Первая бригада - 1/4 в день

Вместе - 1/25 в день

Узнаем за сколько, вторая бригада выполнит задание:

  1. 1/25 - 1/40 = 8/200 - 5/200 = 3/200 - вторая бригада в день.

Теперь мы можем узнать работу второй бригады:

2. 3/200 = 200/3 = 66 2/3

Ответ: Да, вторая бригада может выполнить задание, за 67 дней.

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