Question

Помогите решить!!Срочно!!​

Answer 1

$\frac{2}{y^{2}-yx} - \frac{2}{yx-x^{2}} = \frac{2}{y(y-x)} - \frac{2}{x(y-x)} = \frac{2x-2y}{xy(y-x)} = \frac{-2(-x+y)}{xy(y-x)} = -\frac{2}{xy}$

При x = 2; y = -3:

$-\frac{2}{2*(-3)} = \frac{-2}{-6} = \frac{2}{6} = \frac{1}{3}$

Ответ: $\frac{1}{3}$