Question

43 балла
ПОМОГИТЕ ПОЖАЛУЙСТА​

Answer 1

Ответ:

Объяснение:

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Answer 2

$\(\frac{sin4\beta+2sin2\beta}{2(cos\beta+cos3\beta)}=\frac{2sin2\beta cos2\beta+2sin2\beta}{4cos2\betacos\beta}=\frac{2sin2\beta(cos2\beta+1)}{4cos2\betacos\beta}=\\=\frac{tg2\beta(cos2\beta+1)}{2cos\beta}=\frac{tg2\beta cos^2\beta}{cos\beta}=cos\beta\cdot tg2\beta\)$

$\(\frac{2cos\psi+cos3\psi + cos5\psi}{cos3\psi+sin\psisin2\psi}=\frac{2cos\psi+2cos4\psi cos\psi}{cos3\psi+0,5cos\psi-0,5cos3\psi}=\frac{2cos\psi(1+cos4\psi)}{0,5cos3\psi+0,5cos\psi}=\frac{2cos\psi(1+cos4\psi)}{0,5(cos3\psi+cos\psi)}=\\=\frac{2cos\psi(1+cos4\psi)}{0,5\cdot2cos2\psi cos\psi}=\frac{2cos\psi(1+cos4\psi)}{cos2\psi cos\psi}=\frac{2(1+cos4\psi)}{cos2\psi}=\frac{4(1+cos4\psi)}{2cos2\psi}=\frac{4cos^22\psi}{cos2\psi}=4cos2\psi\)$