Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!

Answer 1

$y = {x}^{2} \sqrt{x} \\ y' = ( {x}^{2} )' \times \sqrt{x} + {x}^{2} \times ( \sqrt{x} )' \\ y' = 2x \times \sqrt{x} + {x}^{2} \times \frac{1}{2 \sqrt{x} } \\ \\ y'(4) = 2 \times 4 \times \sqrt{4} + {4}^{2} \times \frac{1}{2 \times \sqrt{4} } = \\ = 16 + 16 \times \frac{1}{4} = 16 + 4 = 20$