Question

$\frac{1}{2 + \sqrt{3} } + \frac{2}{\sqrt{3} - 1 }$
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Answer 1

$\frac{1}{2+\sqrt{3} }+\frac{2}{\sqrt{3} -1}=\frac{1*(2-\sqrt{3}) }{(2+\sqrt{3})(2-\sqrt{3})}+\frac{2*(\sqrt{3}+1) }{(\sqrt{3}-1)(\sqrt{3}+1)}=\frac{2-\sqrt{3}}{4-3}+\frac{2(\sqrt{3}+1) }{3-1}=2-\sqrt{3}+\sqrt{3}+1=3$