Question

(5 целых 7/12-3 целых 5/18) * 6 целых 7/15 : ((4 целых 2/9 + 1 целая 1/6) : 16 целых 3/5) решение и ответ

Answer 1

$(5\frac{7}{12} - 3\frac{5}{18}) * 6\frac{7}{15} : ((4\frac{2}{9}+1\frac{1}{6}) : 16\frac{3}{5}) = 45\frac{139}{150}\\\\1) 5\frac{7}{12} - 3\frac{5}{18} = 5\frac{21}{36} - 3\frac{10}{36} = 2\frac{11}{36}\\\\2) 4\frac{2}{9} + 1\frac{1}{6} = 4\frac{4}{18} + 1\frac{3}{18} = 5\frac{7}{18}\\\\3) 5\frac{7}{18} : 16\frac{3}{5} = \frac{97}{18} : \frac{83}{5} = \frac{97*5}{18*83} = \frac{485}{1494}\\\\4) 2\frac{11}{36} * 6\frac{7}{15} = \frac{83}{36} * \frac{97}{15} = \frac{83*97}{36*15} = \frac{8051}{540}$

$5) \frac{8051}{540} : \frac{485}{1494} = \frac{8051*1494}{540*485} = \frac{83*1494}{540*5} = \frac{83*83}{30*5} = \frac{6889}{150} = 45\frac{139}{150}$

Ответ: $45\frac{139}{150}$