Question

Помогите, пожалуйста, решить уравнение

Answer 1

$\frac{3y-2}{y-3}-\frac{y-4}{y+3}+\frac{15y-1}{(3-y)(3+y)}=0\\\\\frac{3y-2}{y-3}-\frac{y-4}{y+3}-\frac{15y-1}{(y-3)(y+3)} =0\\\\\frac{3y^{2}+9y-2y-6-y^{2}+4y+3y-12-15y+1}{(y-3)(y+3)}=0\\\\\frac{2y^{2}-y-17 }{(y-3)(y+3)}=0\\\\\left \{ {{2y^{2}-y-17=0 } \atop {y\neq-3;y\neq3}} \right.$

$2y^{2}-y-17=0\\\\D=(-1)^{2}-4*2*(-17)=1+136=137\\\\y_{1}=\frac{1-\sqrt{137}}{4}\\\\y_{2}=\frac{1+\sqrt{137} }{4} }$