Question

Разложить на множители:

a^4 - 1/16
x-x^2+y^2-y

Answer 1

$a^4 - \frac{1}{16} = ({a}^{2} )^{2} - {( \frac{1}{4}) }^{2} = \\ = ( {a}^{2} - \frac{1}{4} )(( {a}^{2} + \frac{1}{4} ) = \\ = (a - \frac{1}{2} )(a + \frac{1}{2} ) ({a}^{2} + \frac{1}{4} )$

$x-x^2+y^2-y = \\ = (y^2-x^2) - (y + x) = \\ = (y + x)(y - x) - (y + x) = \\ = (y + x)(y - x - 1)$