Question

Помогите пожалуйста

Answer 1

$\frac{2x+10}{x^2+x-20}=\frac{2(x+5)}{(x+5)(x-4)}=\frac{2}{x-4}\\\\\\\frac{2x^2+9x-18}{4x^2-9}=\frac{2(x+\frac{3}{2})(x+6)}{(2x-3)(2x+3)}=\frac{(2x+3)(x+6)}{(2x+3)(2x-3)}=\frac{x+6}{2x-3}\\\\\\\frac{36a^2-12a+1}{6a^2+11a-2}=\frac{(6a-1)^2}{6{(a-\frac{1}{6})(a+2)}}=\frac{(6a-1)^2}{(6a-1)(a+2)}=\frac{6a-1}{a+2}$

Answer 2

1) 2(x+5) / ((x+5)(x-4)) = 2/(x-4)

2) ((x+6)(2x-3)) / ((2x-3)(2x+3)) = (x+6)/(2x+3)

3) (6a-1)^2 / ((6a-1)(a+2)) = (6a-1)/(a+2)