Question

Дано: b1=
$\frac{1}{64}$
b2=
$\frac{1}{18}$
b3=
$\frac{1}{6}$

Найти:S6
​

Answer 1

b2 ＝ b1 * q

q ＝ b2/b1 ＝ 1/18 : 1/64 ＝ 64/18 ＝ 32/9

Sn ＝ (b1(q^n - 1))/(q - 1)

S6 ＝ (1/64((32/9)^6 - 1))/(32/9 - 1) ≈ 12