Question

(a-4)^2-3a(a-5); (x^2+9)(x-3)(x+3) "^" это степень ​

Answer 1

$(a - 4) { }^{2} - 3a(a - 5) = {a}^{2} - 8a + 16 - 3 {a}^{2} + 15a = 16 + 7a - 2 {a}^{2}$

$( {x}^{2} + 9)(x - 3)(x + 3) =( {x}^{2} + 9) ×( {x}^{2} - 9) = {x}^{4} - 81$

Answer 2

(а-4)^2 - 3а (а-5) = а^2 - 8а + 16 - 3а^2 + 15а = -2а^2 + 7а + 16

(х^2+9)(х-3)(х+3) = (х^2+9)×(х^2-9) = х^4-81