Question

Решите тригонометрическое неравенство​

Answer 1

|sin3x|<√3/2

-√3/2<sin3x<√3/2

sin(-п/3)=-√3/2

sin(П-П/3)=sinП/3=√3/2

(-П/3+2Пk;2П/3+2Пk)

Answer 2

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