Question

Сократите дробь: (2x^2-9x-5):(3x^2-14x-5)

Answer 1

$(2x^2-9x-5):(3x^2-14x-5)=\frac{2x^2-9x-5}{3x^2-14x-5}=\frac{2x^2+x-10x-5}{3x^2+x-15x-5}=\\\\\frac{x(2x+1)-5(2x+1)}{x(3x+1)-5(3x+1)}=\frac{(2x+1)(x-5)}{(3x+1)(x-5)}=\frac{2x+1}{3x+1}$