Question

Помогите пожалуйста

Answer 1

$2 - ( \frac{1}{64} + x {}^{2} ) = - (x - \frac{1}{8} ) {}^{2} \\ 2 - \frac{1}{64} - x {}^{2} + (x - \frac{1}{8} ) {}^{2} = 0 \\ 2 - \frac{1}{64} - x {}^{2} + x {}^{2} - \frac{1}{4} x + \frac{1}{64} = 0 \\ 2 - \frac{1}{4} x = 0 \\ \frac{1}{4} x = 2 \\ x = 8$