Question

1) (3+х)^2-(х^2+3^2)-3^2=0


1 4 3 4
2) х(х +1 -- ) + -- - -- - ( -- + х^2 )=0
3 9 4 9

Answer 1

1)

$(3 + x) {}^{2} - (x {}^{2} + 3 {}^{2} ) - 3 {}^{2} = 0 \\ 9 + 6x + x {}^{2} - (x {}^{2} + 9) - 9 = 0 \\ 9 + 6x + x {}^{2} - x {}^{2} - 9 - 9 = 0 \\ 6x - 9 = 0 \\ 6x = 9 \\ x = \frac{ 9}{6} \\ x = \frac{3}{2}$