Question

помогите срочно!!!!!!!!!!!!​

Answer 1

$\tt \cfrac{x-2}{x}= \cfrac{3-2}{3}=\cfrac{1}{3}\\\\\\ \cfrac{(t-7)^2}{2s}=\cfrac{(4-7)^2}{2\cdot(-1)}=\cfrac{(-3)^2}{-2}=\cfrac{9}{-2}=-4,5\\\\\\ \cfrac{y+6}{y-2}=\cfrac{4+6}{4-2}=\cfrac{10}{2}=5\\\\\\ \cfrac{x-5}{(2y+3)^2}=\cfrac{2-5}{(2(-2)+3)^2}=\cfrac{-3}{(-4+3)^2}=\cfrac{-3}{(-1)^2}=\cfrac{-3}{1}=-3$