Question

Решить уравнение 3x^2-6x-2=0​

Answer 1

a = 3, b = -2, c = -2

D=b^2 - 4*a*c = 4 + 12 = 16

$x_{1} = \frac{-b + \sqrt{D} }{2*a} = \frac{+2 + \sqrt{16} }{2*3} = \frac{2+4}{6} = \frac{6}{6} = 1$

$x_{2} = \frac{-b -\sqrt{D} }{2*a}  = \frac{2 - 4}{6}  = \frac{-2}{6} = -\frac{1}{3}$