Question

решите тригонометрическое уравнение.
cos (2x-1)=-√2/2

Answer 1

cos(2x-1)=-√2/2

cos(2π-(2x-1))=-√2/2

cos(2π-2x+1)=-√2/2

2x-1=3π/4

2π-2x+1=3π/4

$x=\left \{ {{\frac{3\pi }{8} + \frac{1}{2} = k\pi    } \atop {\frac{5\pi }{8} }+\frac{1}{2}+k\pi  } \right.$