Question

Упростите выражение 2cos^2x/sin2x​

Answer 1

2cos^2x/sin2x

cos^2x=1-sin^2x

sin2x=2sinxcosx

2(1-sin^2x)/2sinxcosx

(1-sin^2x)/sinxcosx

(cos^2x+sin^2x-sin^2x)/sinxcosx

cosx/sinx=ctgx

Answer 2

$\frac{2Cos^{2}x }{Sin2x}=\frac{2Cos^{2}x }{2SinxCosx}=\frac{Cosx}{Sinx}=Ctgx$