Question

a(7+a)-(a-2)^2 при a=-5\11.Прошу помощи, милые люди!

Answer 1

7a+a^2-(a^2-4a+4)=7a+a^2-a^2+4a-4=11a-4

При a = -5/11, 11a-4=11(-5/11)-4=-5-4=-9

Answer 2

$a(7+a)-(a-2)^2$

$\pi p~~a = -\frac{5}{11}~~~~~~~~~~~(-\frac{5}{11})(7+(-\frac{5}{11}))-((-\frac{5}{11})-2)^2= (-\frac{5}{11})(6\frac{6}{11})-(2\frac{5}{11})^2=-2\frac{118}{121}-6\frac{3}{121}=-9$