Question

Прошу, помогите решить

Answer 1

$\sqrt{3x-2}\leq x\\\\3x-2\geq 0\\x\geq \frac{2}{3} \\\\3x-2\leq x^{2} \\-x^{2}+3x-2\leq 0 \ *(-1)\\x^{2}-3x+2\geq 0\\\\x_{1}=1\ x_{2}=2\\\\(x-1)(x-2)\geq 0$