Question

ПОМОГИТЕ ПЛИИИЗ ОЧЕНЬ ОЧЕНЬ НАДО

Answer 1

$13 {z}^{2} + 52z - z - 4 = 0 \\ 13 {z}^{2} + 51z - 4 = 0 \\ d = 2601 + 208 = 2809 = 53$

$z1 = - \frac{52 + 53}{26} = \frac{1}{26}$

$z2 = - \frac{52 - 53}{26} = - \frac{106}{26} = \\ - 4 \frac{2}{26} = -4 \frac{1}{13}$

Answer 2

13z²+52z-(z+4)=0

13z²+52z-z-4=0

13z²+51z-4=0

D=2601+208= 2809

z1= (-51-53)/26= -4

z2= (-51+53)/26= 1/13