Question

Решите систему неравенств, 8 класс

Answer 1

$\displaystyle \tt \left \{ {{x^2-10x-24<0} \atop {2x-16>0}} \right. { {{} \atop {|:2}} \right. \left \{ {{(x-12)(x+2)<0} \atop {x>8}} \right. \left \{ {{+++(-2)---(12)+++>x} \atop {-------(8)+++++>x}} \right. \Leftrightarrow\\ x\in (8;12)$

Ответ: $(8;12)$